Intuition and Treasure Hunting May 20, 2008
Posted by Lee in Education, Mathematics, Trivia.trackback
Google recently announced its Google Treasure Hunt contest, which they describe as a contest to track “problem-solving skills in computer science, networking, and low-level UNIX trivia.” As all self-respecting French Lit majors should do, I signed up, natch. Two minutes later, I was presented with my first problem. I now take you on a three-part journey that shows where my mind goes when presented with a challenge like this.
To begin, the problem as presented:
Fascinating. For those who say “who cares,” well, I understand. Which brings me to my first strategy:
Personalize the problem
A clip-art robot moving (rightward and downward only) to a finish star doesn’t exactly make me want to start counting squares. So, I’ll change the problem a little and give myself a little motivation.
Lee is located at the top-left corner of a 32×44 grid (marked ‘Start’ in the diagram below)*.
He can only move either down or right at any point in time. He desperately wants to meet Amanda Congdon, host of his favorite video blog sometimesdaily.com
(marked ‘Finish’ in the diagram below) but wants to avoid her larger and smarter boyfriend Mario, despite having only the most honorable intentions.
How many possible unique paths can Lee take to Amanda?
Now there’s motivation for me to figure this thing out. Amanda is my American Idol. But even though there are now stakes, the problem is still difficult. So I…
Solve a different problem
The 32×44 grid is daunting. I mean, this thing would be cake if the problem were, say, 2×2:
From my start point, there’s only one way to move to each blue square, since I can only move downward or to the right. I’ll mark that by putting big 1’s on each of those squares.
So now it should be reasonably obvious that there are two ways to move onto Amanda’s square: right then down, or down then right. Let’s mark that with a 2.
So there are two ways to go with a 2×2 puzzle. Let’s increase the difficulty a little, to a 3×3. I’ve filled in the info we know so far. Remember: I can only move down or to the right.
The two unlabeled white squares are easy. Since they are either directly below me or directly to my right, there’s only one way to get to them. Labeled:
For the blue square just above Amanda, there are three ways to get there:
And similarly for the blue square to her left. To wit :
If there are three ways to get just above or just to the left of Amanda, and remembering that I can only move down or right, then there are six ways to reach the final square.
Okay, I’m bored with this already, so on to the next strategy:
Look for Patterns
Who else has noticed that you can get the sum of any square by adding the numbers above it and to its left?
The squares along the edges don’t get any more complicated. A 4×4 grid appears thusly:
And the remaining squares can get filled in by the pattern we noticed.
Maybe this pattern of numbers looks familiar to you. Perhaps if I rotate the image 45°, desaturate the checkerboard a little, and keep our pattern going, you’ll recognize it.

This pattern, commonly known as Pascal’s Triangle has actually been known for a long, long time. The example shown here was published in 1303 by Zhu Shijie (1260-1320), in his Si Yuan Yu Jian. It was called Yanghui Triangle by the Chinese, after the mathematician Yang Hui. (Click to enlarge)
Preview of Part Two
I haven’t given the answer yet: given this start, you may want to try it yourself. Even if not, I want you to try the following small problem and try using your intuition.
If you place 7 points on a circle’s edge and connect them all, what is the maximum number of pieces that the circle’s interior can be cut into?
I’ll get you started. Here are circles that have two, three, and four points on their edge.
This gives us the following information.
Number of Points Regions 2 2 3 4 4 8 5 _ 6 _ 7 _ <-This is the number I want
Next time, I’ll give you the answer to the circle problem. And show you that it and the Amanda problem have a very curious thing in common.
Let’s not spoil it for everyone by posting the answers to either problem in the comments. I’m happy to talk about them through email if you want to make a guess.















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